已知平面四边形$ABCD$，$AB = BC = 2$，$CD = 1$，$AD = \sqrt{3}$，$\angle ADC = 90^\circ$，沿直线$AC$将$\triangle ACD$翻折成$\triangle ACD'$，则直线$AC$与直线$BD'$所成角的余弦值最大...